Write a prog. to continuously print the input no.s and stop printing when the input no. is 42 and exit when the input no. Is 101

Question

the screen will be like:

input:
1
2
3
98
42
45
101
output:
1
2
3
98

Answer 1

code?

Answer 2

Python:

done, exit=False, False
while not exit:
num = int(input(""))
if num==42 : done = True
if not done : print(num,"\n")
if num==101 : exit = True

Answer 3

Not sure if 101 is to be printed when encountered before a 42. But here is the code:

C++:

bool done=false, exit=false;
int num;
while(!exit)
{
cin>>num;
if(num==42) done = true;
if(!done) cout<<num<<endl;
if(num==101) exit = true;
}

Answer 4

in Python ?
or any ?

Answer 5

just python

Answer 6

thanks