Обсуждения
double arr[]={5,2,7,8,11,9};
int n = sizeof(arr) / sizeof(arr[0]);
double sum = 0;
for(int i=0;i<n;i++)
{
sum+= arr[i];
}
double avg = sum / n;
cout<< "avarage ="<< avg<< endl;
return 0;
)
/*what does int n= sizeof(arr[]) /sizeof(arr[0]);
do, can someone explain that line for me*/
0 голосов
3 ответовАктуальное сегодня
Ejercicio Pytho
0 Votes
What is that z for
0 Votes
Suggestions needed
4 Votes
Please rate my code from 1 to 10
2 Votes
How to start
0 Votes
Recursion doubt
2 Votes