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How the pointer holds a string in one address ? char *s = "hello"; char *p = s; printf( "%c" , s[0]); ANSWER = h
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Why some programmer use char array of int instead of using strings,? And how to generate this char array from a string?
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Hi guys! If constant 0x13 and 'c' are char type what will be printf format specifier for each of following constants
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#include<stdio.h>
#include<string.h>
void main()
{
char *str="His";
int i=0;
for(i=0;i<=strlen(str);i++)
printf("%s",str++);
}
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Predict the output of following program? #include "stdio.h" int main() { char arr[100]; printf("%d", scanf("%s", arr));
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#include<iostream>
#include<conio.h>
#include<stdio.h>
void main()
{
int i;
char str[80];
cout<<"enter any name";
gets(str);
for(i=0;str[i]!='\0';i++)
{cout<<str[i]<<"\n";
}
getch();
}
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If I assign a single chat at first index of char array and then I print whole array then only that single char is not printing
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I want to find the longset name of input and its location ,i try but deon`t have any out put can you help me?
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Write a program in kotlin to check the input char is vowel or consonant using when condition
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