Is true && false == 1?

Question

Still not cleared on this

https://code.sololearn.com/cEvv139DcEns/?ref=app

Answer 1

if anyone noticed while using logical operator for evaluation we always use them in parentheses such as if (x<y).

use this:
cout<<(true&&false);

ur result will be 0 as expected.

Answer 2

I think in int and bool got right output rather cout also give correct output
look in cout first call true then &&false thats why output is 1 as true value

You can check this as cout << "but if u directly output true&&false u get "<< false&&true ;
now output is 0 as value of false..

Answer 3

false && false -> false
false && true -> false
true && false -> false
true && true -> true

Answer 4

In the case of cout, operator precedence is the issue.

cout << "but if u directly output true&&false u get "<< true&&false;

is equivalent to

( cout << "but if u directly output true&&false u get "<< true )&&false;

Answer 5

&& checks if both sides are true, but here, just one side is true. So it returns false.

Answer 6

Coder Always these words are confusing. there are 2 ops to compare: && and "and". this is made cause different priorities in the op hirarchy. I think the prob here is the handling of the stream. To get it clear there would be brackets a plus.

Answer 7

and operator is used for comparing two sides and if either one results false the output is false

Answer 8

correct as all of you mentioned guys.
problem is using expressions in COUT in general.

in this cases with COUT I recommend you always to use variables, as you did in first two examples. It will be more clear to read and to find possible mistakes.

b = true && false
COUT << b

Answer 9

b is a throw-away variable and causes confusion as it's another layer of indirection. Just do
std::cout << (true && false);

Answer 10

std::cout << std::boolalpha;
Now you don't get 0 or 1 but true or false.

Answer 11

0&&1 results 0 only as one side is false and the other is true