Js example

Question

var count = 0;
for(i=0; i<3; i++){
for(j=3; j>; j--){
++count;
}
}
alert(++count);//10. why output 10?

Answer 1

Ok..let me explain
I loop First iteration:
i=0 ,I<3 it's okay
Then goes to j loop first iteration
J=3 ,j>0 it's okay and ++count it's mean count=1 and j-- it's mean j=2
Then goes to j loop second iteration
J=2 ,j>0 it's okay and ++count it's mean count=2 and j-- it's mean j=1
Then goes to j loop third iteration
J=1 ,j>0 it's okay and ++count it's mean count=3 and j-- it's mean j=0
Now J=0 ,j>0 it's not okay finally j loop end

Now again go to I loop second iteration:
i=1 ,I<3 it's okay and so on as above

Now it's run untill i=3
And finally count=9

If doesn't understand please study about Nested loops

Answer 2

Welcome.. no problem.. keep learning

Answer 3

Js example

var count = 0;
for(i=0; i<3; i++);{//are you sure here semi colon present?
for(j=3; j>; j--){
++count;
}
}
alert(++count);//10. why output 10?

Answer 4

Js example

var count = 0;
for(i=0; i<3; i++){
for(j=3; j>; j--){
++count;
}
}
alert(++count);//10.

The outer i loop control inner j loop..
That means I loop run 3times and j loop run 3times
Now 3*3=9 times loops run ultimately and after loop exit count has value 9..
After that when it print it also increase to 10
That's why it's showing 10
Hope you understand 😉

Answer 5

Haven't sorry

Answer 6

Okay i go repeat nested loops thanks

Answer 7

No i cant understand why in program do 3*3