Why another constructor is not running during class B initialization?

Question

class A {

public A() {
System.out.println("New A");
}

public A (String name){
System.out.println("New A 1");
}

}
class B extends A{
public B() {
System.out.println("New B");
}
}

class Program {
public static void main(String[ ] args) {
B obj = new B();
}
}

//output
New A
New B

but not also
New A 1

Answer 1

Because only the default constructor is called. You have not initialized an object with the constructor that takes a String parameter.

Answer 2

you have to pass a string as an argument/parameter while you create an object/instance of the class..

Answer 3

you have to call the A constructor with string in order to have New A 1 example A obj = new A ("dfgg") or B obj = new B ("sdfdd")

Answer 4

for that u need to pass string as a parameter there.
like
B obj = new B("hello");

Answer 5

In class B In the no argument constructor the compiler is going to place
public B()
{
super();
sop("New B");
}
it means it's a call to no argument constructor for the parent class. if the parent class doesn't have no argument constructor then it call's default constructor of parent class.