How print(5|3) work?

Question

Explain in detain

Answer 1

5 = 101 in binary
3 = 011 in binary

1 or 1 = 1
0 or 1 = 1
1 or 0 = 1
0 or 0 = 0

1 0 1
0 1 1 # or'd
so 7 = 1 1 1

Answer 2

when the bitwise operator | (which is “or”) is used it takes a look at the binary of the number
What it does next is check every position of both numbers for 1s
if it finds a 1 in one of the position on either side of the | operator it sets that position to 1
for example

5|10

binary of 5 is 0101 (or 101)
binary of 10 is 1010

the | operator will check each position in the binary code ( 0101 has 4 positions; as does 1010)(you can always add more zeroes to the front of the binary :))
if it finds a 1 in position 1 it will turn that to one

position 1 in 0101 is a 0, but in 1010 it is a 1, so it turns position 1 into 1

position 2 in 0101 is a 1, so turns position 2 to 1

etc etc

which gives us, at the end of the calculation: 1111 which is binary for 15

5|10 == 15

other examples when looking st binary numbers
0000|1111 == 1111 (0|15==15)
1100 | 1111 == 1111 (12|15==15)