I simply,don't understand how this code makes these result

Question

int x=0;
int y=0;
if(++x>4&&++y>2)
x++;
System.out.println(x);
And result is 1
How???

Answer 1

First the ++x in if loop gets incremented which makes x value set to 1 . Now after that the condition becomes false but remember that x is already incremented by 1.

Answer 2

but how is incremented,when condition is not true?

Answer 3

Samir Krasnic
Abhay has given a really good answer.

Could I ask you to review lesson 7.1 of the Java tutorial.
The section regarding prefix & postfix of incrementation or decrementation.

Your example code has an example of the effects of prefix incrementation, which means x was increased by 1 before the condition was evaluated.

The condition proved to be false, so the code moves on to the next section.

Since x is now 1 because of the prefix increment, the output is 1.

Answer 4

Samir Krasnic compiler starts evaluating the expression from left to right . First it sees "++x" and increments value of x by 1 . Then it sees x>4 is false .

As you can see x has been incremented prior to the condition becoming false .

Just because something is false doesn't implies nothing will happen .

Answer 5

Thanks,i thought different