Why this return makes invalid syntax?

Question

def countdown():
i=5
while i > 8:
print("i = {}".format(i))
yield i
i -= 1
print(" =>i = {}".format(i)
return i

for j in countdown():
print(j)

Answer 1

1) missing ) in line
print(" =>i = {}".format(i)

2) you can't use return with a argument if you use that function as a generator so replace->
return i
with->
yield I
return

so the code will be->
def countdown():
i=5
while i > 8:
print("i = {}".format(i))
yield i
i -= 1
print(" =>i = {}".format(i))
yield i
return

for j in countdown():
print(j)

Answer 2

thanks