F&A Diskussionen
What does !x mean, i understand !(x>30) means x can't be greater than 30 but this '!x' is just confusing me
1 Stimme
2 Antworten
Given two numbers X and Y, write a function that: 1 returns even numbers between X and Y, if X is greater than Y else it returns
-4 Stimmen
5 Antworten
Write a query to output the apartments whose prices are greater than the average and are also not rented, sorted by the 'Price'.
0 Stimmen
1 Antwort
Fill in the blanks to print "you rock" is variable "a"is greater than 15,and variable "b" is less than or equal to 72...........
0 Stimmen
1 Antwort
Add a field - Date of completion with Date type to the registration table.Ensure Date of completion is greater that DOJ.
0 Stimmen
1 Antwort
How can I order 2 numbers from the lesser one to the greater one in JavaScript? Please help me to correct my try...
1 Stimme
3 Antworten
Assume If u have employee table. U have to fetch the results whose salary is greater than 5000. Without using where clause.
0 Stimmen
3 Antworten
Write a query to output the apartments whose prices are greater than the average and are also not rented, sorted by the 'Price'.
-6 Stimmen
3 Antworten
. Given an array and an integer, find the smallest subarray with length 2 whose absolute difference is greater than the given in
-1 Stimme
2 Antworten
I typed this exact code but it doesn't work no matter what I do. if 10 > 5: print("10 is greater than 5")
0 Stimmen
3 Antworten
Please write this program ..
Ask the user to enter a list containing no's between 1&12 . Then replace all of the entries in the list that are greater then 10 with 10
1 Stimme
9 Antworten
Help!!! Using C# ....write a program that will sum numbers btn 1&50 and if sum is greater than 300 the loop exist
-3 Stimmen
3 Antworten
Take a 4 digit no. Write program to display a no. whose digits are 2 greater than the corresponding digits of the no.ex.123 246.
-2 Stimmen
4 Antworten
Can sme1 give me the command to this query
Get the first name, city, country, and invoiced amount of customers living either in Brazil or in Paris and with a total invoice greater than $38.
1 Stimme
12 Antworten
Where can I get greater or lesser sign on S5. I don't see it on the keyboard? I can't apply ArrayList without it.
0 Stimmen
2 Antworten
how do I ensure that a user does not input a number less than 1 or greater than 10 in this code.
int a;
cin>>a;
1 Stimme
2 Antworten
arguments and returning the greater one. Arguments are of template types T and U, respectively. if (a > b) { return b; template
0 Stimmen
1 Antwort
Drag and drop from the options below to select all items from the ''items'' table for which the cost is greater than the average
-1 Stimme
1 Antwort
i want to write a line of code that looks like this
if (a>10){
I know that in c++, you cannot just have greater than (>) or less than (<). j
it must be (>=) or (<=). But the code I need to write does not include the equal to(=). it just has to be greater than 10. What do I do?
1 Stimme
2 AntwortenHow do you check if the user has entered valid integer ? For example if the user types in a charecter or a string or an integer greater than the max bound of the integer type.
1 Stimme
5 Antworten
l want to program code that compare two values x and y , return 1 if x is greater than y else return 0 if x is equal to y or else return -1 if x less than y . Then program must accept user input
0 Stimmen
6 Antworten
how cone the answer is 5 ?
it is greater than for so the while condition is not satisfied hence the ans will be the input itself i.e. 2
0 Stimmen
2 Antworten
look at if statement
if 10 > 5:
print("10 greater than 5")
print("Program ended")
it work perfectly, but when I changed if statement to 10 = 5:
or 10 =>5:
the program runs error, otherwise using ">=", "<=", "==","<" the progam work fine.
please explain
2 Stimmen
4 Antworten
why does this code output that there is an error because the else statement doesn't have a corresponding if statement?. How do i correct this?
#include <iostream>
using namespace std;
int main() {
int a;
for (int x =0; x<5;x++){
cin>>a;
if (a<1){
cout<<"a cannot be less than 1\n";
}
else if (a>10){
cout <<"a cannot be greater than 10\n";
}
}
else{
cout<<"code can run now"<<endl;
}
return 0;
}
3 Stimmen
8 Antworten2
-6 Stimmen
2 Antworten
Heute heiß
Help please?
4 Votes
Ejercicio Pytho
0 Votes
What is that z for
0 Votes
Suggestions needed
4 Votes
Game development
0 Votes
Ruby programming?
3 Votes