What's wrong with this code?

Question

#include <stdio.h>
void bubble_sort (int a[], int n)
{ int i = 0, j = 0, tmp;
for (i = 0; i < n; i++) { // loop n times - 1 per element
for (j = 0; j < n - i - 1; j++)
{ // last i elements are sorted already
if (a[j] > a[j + 1]) { // swop if order is broken
tmp = a[j];
a[j] = a[j + 1];
a[j + 1] = tmp; } } }}

main() {
int a[100], n, i, d, swap;
printf("Enter number of elements in
the array:\n");
scanf("%d", &n);
printf("Enter %d integers\n", n);
for (i = 0; i < n; i++)
scanf("%d", &a[i]);

bubble_sort(a, n);
printf("Printing the sorted array:\n");
for (i = 0; i < n; i++)
printf("%d\n", a[i]);
return 0;}

Answer 1

Here's the same code but a little bit more readable:
#include <stdio.h>
void bubble_sort (int a[], int n){
int i = 0, j = 0, tmp;
for (i = 0; i < n; i++) { // loop n times - 1 per element
for (j = 0; j < n - i - 1; j++){ // last i elements are sorted already
if (a[j] > a[j + 1]) { // swop if order is broken
tmp = a[j];
a[j] = a[j + 1];
a[j + 1] = tmp;
}
}
}
}

main() {

int a[100], n, i, d, swap;

printf("Enter number of elements in the array:\n");

scanf("%d", &n);

printf("Enter %d integers\n", n);

for (i = 0; i < n; i++)
scanf("%d", &a[i]);

bubble_sort(a, n);

printf("Printing the sorted array:\n");
for (i = 0; i < n; i++)
printf("%d\n", a[i]);

return 0;
}

It is the exactly same one as yours, and it works just fine. Maybe the input method is wrong: make sure you input your numbers as such:
3
3 2 1
Another example:
5
6 4 3 1 2 8

Answer 2

Could you save your code on Sololearn and paste the link here, please?