How to check given string in array or not?

Question

Java

Answer 1

You could use Arrays.binarySearch() (Requires an ordered array)

Returns index of string that matches, or a negative number if not found.

An example:

import java.util.Arrays;

public class ExampleOfIndexOf {

public static void main (String args[]) {
String[] stringArray = {"hair", "eye", "mouth", "nose"};

Arrays.sort(stringArray);

System.out.println(Arrays.binarySearch(stringArray, "mouth")); // 2
System.out.println(Arrays.binarySearch(stringArray, "mou")); // -3 in this case: -(array length - 1)
}
}

Answer 2

bahha If you need to compare string content, use .equals() instead of == :)

Check this example:

https://code.sololearn.com/cXXyWUUC6FXE/?ref=app

Answer 3

here is a primitive and less efficient way to do it.
public class Program
{
public static void main(String[] args) {
String str = "yyy";
String array [] = {"yyy"};

for(int i = 0; i < array.length ; i++){
if(array[i] == str ){
System.out.println("found");
} else{
System.out.println(" not found");
}
}
}
}