+ 4
Please help me to correct my code
Recursive void function that print hello ntimes https://code.sololearn.com/czE7WqmwJ5aS/?ref=app
10 Answers
+ 5
If you reached zero, you have to abort the function:
void count(int n){
if (n==0) {
printf("there is nothing");
return;
}
else
printf("hello\n");
count(n-1);
}
+ 14
count(n-1) for decrement n and output "hello" until n=0
+ 12
You are welcome đ
+ 11
void count(int n){
if (n==0)
printf("there is nothing");
else
{
printf("hello\n");
count(n-1);
}
}
int main(){
int n;
printf("entrer an integer :\n");
scanf("%d",&n);
printf("we have :\n");
count(n);
}
+ 2
You can't print a void function.
Just call the function because you have all print statements inside the function.
if(n == 0) after printf() you should also stop the function otherwise you will get an infinite loop.
+ 2
Thanks guys
+ 1
How can I stop the function because I dropped in infinite loop
Hello hello.......
+ 1
Why please count (n-1)
+ 1
##Are we should change the parameters while we are calling the recursive function
Can we write count(n+1)
##So what the difference between count (n-1) and count (n+1)
##is the purpose only to avoid infinite loop
+ 1
There are all sorts of recursive functions, but they have one thing in common:
They need to have a base case, that determines when they should stop.
Here the base case is (if n==0).
So if n wouldn't decrease, the recursion would never end.
If the base case was (if n>=1000), you could use (n+1) as well, but then (n-1) would be wrong (unless you'd start with n>=1000 of course đ).