How this expression works......

Question

int a=0
int b[3] ={1,2,3};
int c = ++b[++a] + ++a + b[--a] ;
printf ("%d", c) ;

OUTPUT : 8

Answer 1

int a=0;
int b[3] ={1,2,3};

int c = ++b[++a] + ++a + b[--a];

Here ++a = 1;
And next ++a will be 2
And next --a will be 1

from the b array b[1] = 2

So c = ++b[1] + 2 + b[1]

Here ++b[1] = 3 and b[1] = 3 because first increment the value by 1 then again assign to b[1]

So

c = 3 + 2 + 3 = 8