[SOLVED] Python Phone Number Validator

Question

Hi! This is the only challenge I need to do, to finish the python course. The valid number starts with 1or8or9 and has the length of 8. My code passed the first 4 tests, but it failed the 5th test. I can't see the phone number in the 5th test. What can be the problem?

Current code:
import re

number = input()
if re.search("([189])[\d]+", number) and len(number) == 8:
print("Valid")
else:
print("Invalid")

Answer 1

https://code.sololearn.com/cA3A20a15A2a

You can find answer in the above link.

Answer 2

import re

pattern = r"^[189][0-9]{7}quot;

if re.match(pattern, input()):
print("Valid")
else:
print("Invalid")

===========================================
I hope this helps you all.

^ is for starts with [189],
[0-9] digits for {7} repetiotions

$ to end total of [189] + [0-9]{7} which is equals to 8.

Hope you have understood my answer😊

Answer 3

import re
a = input()
pattern = r"[189]"
if re.match(pattern,a):
if len(a) == 8:
print("Valid")
else:
print("Invalid")
else:
print("Invalid")

Answer 4

import re
#your code goes here
number = input()
if re.match(r"^[1|8|9]\d{7}quot;, number):
print("Valid")
else:
print("Invalid")

Answer 5

import re

pattern = r"^[189][0-9]{7}"

str = input()
match = re.search(pattern, str)

if match:
print("Valid")
else:
print("Invalid")

What wrong with this code?

Answer 6

i still get one case not correct this is my code where is the mistake ?
import re
#your code goes here
pattern = r"^1|8|9 + [0-9]{7}quot;
num = str(input())
if re.search(pattern, num):
print("Valid")
else:
print("Invalid")

Answer 7

Here is my answer to that guys:

import re

number = input()
pattern = r"^[189][0-9]"
match = re.match(pattern, number)

if len(number) == 8 and match:
print("Valid")

else:
print("Invalid")

Answer 8

@Arya Huda Arrasyid
You need a $ at the end of your regex, otherwise, the phone number can start with the correct 8 digits but then go on indefinitely.

It can only be 8 digits

Answer 9

Most probably you're getting this failure in last test case cause re.search() searches for the whole string even if the string contains multi-lines and tries to find a match of the substring in all the lines of string but you want your numeric number to only START with 1,8 or 9. better to use re.match() instead

Answer 10

import re
num = input ()
pattern = r"^[1|8|9][0-9]*quot;
if re.match(pattern,num) and len(num)==8:
print("Valid")
else:
print("Invalid")

Answer 11

I think this is simplest:

import re

phone = input()
pattern = r"^[189][0-9]{7}quot;

if re.match(pattern, phone):
print("Valid")
else:
print("Invalid")

Answer 12

import re
#your code goes here
number = input()
pattern = r"^(1|8|9)"
match = re.match(pattern, number)
if match and len(number) == 8:
print("Valid")
else:
print("Invalid")

Answer 13

I recommend to test the code on the SL Playground with a few data inputs and a few print statements and see what happend and solve that.

Sp you could see that 01234567 gives a valid number, what unfortunately is not true from task description.
The solution for it will be to code that the number has to begin with 1 or 8 or 9.

Answer 14

import re
#tu código va aquí
pattern = "\d\1|8|9{1,9}quot;
number = input()

if re.search(pattern, number) and len(number) == 8:
print("Valid")
else:
print("Invalid")

Answer 15

Try this:
import re
#your code goes here
str = input()
pattern = r"^(1|8|9)+\d{7,7}quot;
if re.match(pattern , str):
print("Valid")
else:
print("Invalid")

Answer 16

Okime Obia It's the python library for regular expressions

Answer 17

import re
print("Valid" if re.match(r'[789]\d{7}#x27;, input()) else 'Invalid')

Answer 18

Mi respuesta es:

import re
pattern = r"(1|8|9)[0-9]{7}quot;
entrada = input()
if re.match(pattern, entrada):
print("Valid")
else:
print("Invalid")

Answer 19

import re
num = input ()
pattern = r"^[1|8|9][0-9]*quot;
if re.match(pattern,num) and len(num)==8:
print("Valid")
else:
print("Invalid")

Answer 20

import re
x=input()
if re.fullmatch("[189]\d{7}",x):
print('Valid')
else:
print("Invalid")