Need help on the Loan Calculator for Java

Question

https://code.sololearn.com/cXzemj7iFP2Y/?ref=app

The expected output is 53144 but my output is 53145

Answer 1

This code worked:

import java.util.Scanner;

public class Program
{
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
int amount = scanner.nextInt();
//your code goes here
int rem_amt = amount;
for (int i = 1 ; i <= 6 ; i++) {
int paid = (int)Math.ceil(rem_amt);
rem_amt = paid ;
}
System.out.println(rem_amt*729/1000);
}
}

Answer 2

import java.util.Scanner;

public class Program
{
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
int amount = scanner.nextInt();
int payment=0;
//your code goes here
for (int i=0; i<3; i++){
payment= amount/10;
amount-= payment;
}
System.out.println(amount);
}
}

Answer 3

So pissed off! Needs elements it hasn't tougth you yet 😑

Answer 4

import java.util.Scanner;

public class Program
{
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
int amount = scanner.nextInt();
//your code goes here
for(int i=1; i<4; i++){
int payment= (amount*10)/100;
amount= amount-payment;
}
System.out.println(amount);
}
}

my code totally worked and I made it as simple as I could

Answer 5

import java.util.Scanner;

public class Program
{
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
int amount = scanner.nextInt();
//your code goes here
for (int x = 0;x < 3;x++) {
amount -= ((amount * 10) / 100);
};
System.out.println(amount);
}
}
//Simple

Answer 6

Here is tha answer, no need to import lang class.

import java.util.Scanner;
import java.lang.*;

public class Program
{
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
int amount = scanner.nextInt();
//your code goes here

for(int i=0;i<6;i++){
int payment =(int)(10*amount )/100;
if((amount%10)!=0){
amount =amount-1;
}
amount = amount- payment ;

}
System .out .print(amount);
}
}

Answer 7

Scanner scanner = new Scanner(System.in);
int amount = scanner.nextInt();
int remAmount = amount;
for (int i = 0; i < 6; i++)
remAmount -= (remAmount * .10);
System.out.println(remAmount);

Answer 8

https://code.sololearn.com/cp6GXE4Rc84v/?ref=app

The reason why you get 54145 is because of Integer division. It ignores decimals (rounding down). Ultimately when you do a minus, you get an extra 1.

1: 100000 - 100000/10 = 90000
2: 90000 - 90000/10 = 81000
3: 81000 - 81000/10 = 72900
4: 72900 - 72900/10 = 65610
5: 65610 - 65610/10 = 59049
6: 59049 - 59049/10
= 59049 - 5904 (missing precision)
= 54145 (extra 1, expected 54144)

To bypass, you can do "amount = amount * 90 / 100".

Do not hard-code -1 or +1.

One good example will be 0. After 6 months, it will still be 0. By hard-coding -1, it results in -1 which is wrong.

Answer 9

The issue of getting an incremented value instead of the intended one is directly connected with your usage of integers instead of doubles. If you receive a int value the java terminal outputs it after rounding, making it possible for incremented values to be present.

There are two ways you can see through this issue:

The first one is using 90% percent of the value instead of taking 10% than subtracting it from the rest, which is inevitably, and mathematically, the same thing. The only difference is you will receive cleaner code.

import java.util.Scanner;

class Program {
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
double amount = scanner.nextInt();

for (int i = 0; i < 6; i++) {
amount = amount * 0.9;
if (i == 5) {
int final_loan = (int)amount;
System.out.println(final_loan);
}
}
}
}

You can use this one here. This will be a great solution for some examples but the rest still yield an error, I tried but couldn't find any answer in the level of a beginner so you have to use math.ceil

2nd solution:

Replacing the for loop with this in the previous code will yield the answer:

int rem_amt = amount;
for (int i = 1 ; i <= 6 ; i++) {
int paid = (int)Math.ceil(10/100.0*rem_amt);
rem_amt -= paid ;

Answer 10

import java.util.Scanner;

public class Program
{
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
int amount = scanner.nextInt();
//your code goes here
for(int i=0;i<6;i++){
amount = (int)(amount*0.9);

}
System.out.println(amount);
}
}

Answer 11

import java.util.Scanner;

public class Program
{
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
int amount = scanner.nextInt();
//your code goes here
int i=0;
int Newamount;
while(i<6){
amount=amount*90/100;
++i;
if(i==5){
Newamount=amount*90/100;
System.out.println(Newamount);
}
}

}
}

Answer 12

import java.util.Scanner;

public class Program
{
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);

//your code goes here
int amount = scanner.nextInt();
int i = 1;
while (i <= 3)
{
amount = (int)(amount *0.9);
i++;
}
System.out.println(amount);
}
}

Answer 13

cmdr tigerray1,

The question in SoloLearn is:
"Use a loop to calculate the payment and remaining amounts for each month.
Also, use integers for amounts."

Didn't state for the 10% (or 90%) intermediate factors can't be double. However, final result must be in integer.

If you realised, in another solution above, the poster used "Math.ceil(10/100.0*rem_amt)". The denominator, 100.0, is a double as well.

If you want to avoid using 0.9, you can use 90/100.0 in my coded solution. It's the same.

Answer 14

import java.util.Scanner;

public class Program
{
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
int amount = scanner.nextInt();
//your code goes here
int payment = 0;
for (int x=0; x<=5; x++)
{payment = amount/10;
amount = amount-payment;}
{System.out.println (amount);
}
}}

This is what I came up with. It works but my end output is 54145, but it expects 54144. I honestly think there's an issue with the imbedded compiler

Answer 15

The problem with this is there's limitations. This assignment does not use any special class/ method calls, and the numbers have to be int. Normally you could use decimal numbers for the math, but this forces the compiler to look for a double that isn't there. Go to java > conditionals and loops>10 end of ...
to see the parameters. don't use anything that hasn't been taught to that point

Answer 16

Ah I see, tyvm

Answer 17

Ok

Answer 18

OK

Answer 19

int amount = scanner.nextInt();

for (int i = 0; i < 6; i++){
// type cast amount to a double
double payment = (double)amount / 10;
double remaining = amount - payment;
//type cast amount back to an int
amount = (int)remaining;
} System.out.println(amount);
/* this was amount always begins a new iteration or the loop as an int but is calculated as a double so the decimal parts are subtracted correctly, and eliminating the need to use Math.floor or Math.ceil. */

Answer 20

Easiest solution! Not a single loop is used. It is what a novice should do.....ha ha ha

import java.util.Scanner;

public class Program
{ public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
int amount = scanner.nextInt();
int fm=(int)Math.ceil(amount-1-amount*0.1);
int sm=(int)Math.ceil(fm-1-fm*0.1);
int tm= (int)Math.ceil(sm-1-sm*0.1);
int fom=(int)Math.ceil(tm-1-tm*0.1);
int fim=(int)Math.ceil(fom-1-fom*0.1);
int sim=(int)Math.ceil(fim-fim*0.1);

System.out.println(sim);
}
}