Can someone please tell me what is the mistake in the code given in description , the output is also given

Question

num1 = int(input("Enter number 1"))
num2 = int(input("Enter number 2"))
num3 = int(input("Enter number 3"))
if num1**2 == num2**2 + num3**2 : print("(str(num1),str(num2),str(num3)) are Pythagorean triplets")
else :
if num2**2 == num1**2 + num3**2 : print("(str(num1),str(num2),str(num3)) are Pythagorean triplets")
else :
if num3**2 == num1**2 + num2**2 : print("(str(num1),str(num2),str(num3)) are Pythagorean triplets")
else : print("(str(num1),str(num2),str(num3)) are not Pythagorean triplets")

Output :-

File "source_file.py", line 7
else :
^
SyntaxError: invalid syntax
Process finished with exit code 1.

Answer 1

Indentation is not proper.
You can use "else if" in python like this "elif".

num1 = int(input("Enter number 1\n"))
num2 = int(input("Enter number 2\n"))
num3 = int(input("Enter number 3\n"))
if num1**2 == num2**2 + num3**2:
print("(", num1, ",", num2, ",", num3, ") are Pythagorean triplets")
elif num2**2 == num1**2 + num3**2:
print("(", num1, ",", num2, ",", num3, ") are Pythagorean triplets")
elif num3**2 == num1**2 + num2**2:
print("(", num1, ",", num2, ",", num3, ") are Pythagorean triplets")
else:
print("(", num1, ",", num2, ",", num3, ") are not Pythagorean triplets")

Answer 2

?