why when I try to make my_id += 1 gives me an error

Question

here is my code :
my_dict = {
'x': 0,
'y': 0
}
temp = {}
my_id = 0

def new(my):
for i in range(5):
my['x'] = int(input(f'x{i} : '))
my['y'] = int(input(f'y{i} : '))
temp[f'{my_id}'] = my
print(temp)
#my_id += 1

new(my_dict)

why when I try to make my_id += 1 gives me an error

Answer 1

Alisa Zaiceva In Python, you can read a global variable with no problem, but when you write to it Python makes a local variable instead, this avoids the risk of accidentally modifying a global variable. As JaScript mentioned, you can use the global keyword to declare global instead of local.

Answer 2

Alisa Zaiceva ,

may be a bit late, but have a look at it. you can pass the my_id var as a second argument to the function and use it there. you should not work with global variables, as long as there is an other option:

my_dict = {
'x': 0,
'y': 0
}
temp = {}
my_id = 0

def new(my, my_id):
for i in range(5):
my['x'] = int(input(f'x{i} : '))
my['y'] = int(input(f'y{i} : '))
temp[f'{my_id}'] = my
print(temp)
my_id += 1

new(my_dict, my_id)

# if you need to get the last value from my_id in the main scope, you can return the value from the function

Answer 3

The variable should be deckared global as here:

def new(my):
global my_id
for i in range(5):
my['x'] = int(input(f'x{i} : '))
my['y'] = int(input(f'y{i} : '))
temp[f'{my_id}'] = my
print(temp)
my_id += 1

my_id = 0
my_dict = {
'x': 0,
'y': 0
}
temp = {}
new(my_dict)

Answer 4

but they are also defined above the function. Shouldn't they be global?

Answer 5

Thank you very much