Why output of the code is c ?

Question

#include <stdio.h>

int main(){
float a=0.7;
if(a<0.7)
printf("c");
else
printf("c++");

return 0;
}

Answer 1

This is due to the precision of floating point decimals. You need to take into account the epsilon.

If you were to print out the value of a you would see that it shows accuracy to about 6 places past the decimal.
printf("%f", a);

Likewise in your comparison you are not telling the compiler that 0.7 is a float type so double is inferred.
Use if(a<0.7f) and it should run as you are expecting.

Answer 2

@Chaotic

does the f at the end of 0.7f,

mean float?

could you do the same for doubles and decimals?

Answer 3

@Chaotic

Thank you,

Also, would " df " work for a double floating point?

Answer 4

Yes the f tells the compiler that the number is a float type.
Without the f an number with a fractional part or floating point will be inferred as a double type. Decimal is not a built in type for c or c++ and would require an additional header file(s) so this doesn't really apply.