How to write this line properly? (If)

Question

if N==true or n==true or NO=true or No==true

you have to write it like that? Or can you do something like

if N, n, NO, No == true

thanks in advance for answers

Answer 1

the first way, but there is probably an easier way. I assume this is a "would you like to try again" type of input?

if it is, and you have a variable such as

again=input()

And one of n, N, No, no was input, you could handle it with a simpler if statement.

if again[0].lower() == "n":

This would take the first letter that is input

again[0]

then it would make it lower case

.lower()

then it would simply check if the first letter that was input was "n"

here is an example-

again=input("Like to play again")
if again[0].lower() == "n":
print("no more")
else:
print("Yes more")

Also, true and false in Python have capital T and F. True and False.

checking with or will work, but there are other ways. if you wanted specifics instead of just first letter confirmation, you could use a list.

options=["n","N","No","no","NO"]
again=input("Play again?")
if again in options:
//play again