Explaination Is Needed

Question

int a=0;
int b=1;

for (int i=0;i<=b+1;i++){
if (i==2){
System.out.println(a);}

else{
System.out.println(a+b);}

}
Output is 110

Please explain it

Answer 1

3 loops
a=0, a+b=1
'if' prints '0' 'else' prints '1'

1st loop-->□ 'if' is false then print 'else'
□ print 1

2nd loop-->□ 'if' is false then print 'else'
□ print 1

3rd loop-->□ 'if' is true
□ print 0
Output:
110

Answer 2

for loop will run 3 times for value of i=0, 1 & 2......
for value of i =0 ------> output = 0+1 =1.
(if condition. false for i= 0,1)
i =1 --------> output = 1
I =2 --------> if condition becomes true
so output = a =0
output = 110

Answer 3

In the first iteration of the cycle i != 2 (i = 0) so it prints on the screen a + b (0 + 1 = 1), in the second iteration of the cycle (i = 1) the same case is repeated

At this moment the output is: 11

In the last iteration i == 2, so print a (a = 0), which results in 110

Answer 4

firstly see the for loop , syntax for forloop is (initial value; final value ;incresing in that steps)

first step
(int a=0,int b=1) we have given 0,1 values to our variables a and b respectively.

second step =>The for loop
1)in this the initial value for i is give as 0
2)since 0 <2 we go inside the for loop and execute the statements...
3)inside the for loop we have (if) and (else) statement
if(0==2) then print value of a
else print the value of b
since 0!=2 we go for else statement and print value of b i.e 1

now we go back to for loop and incremwnt the value of i by 1 i.e now it will 0+1=1
now this value will be compared and similar steps to bw followed and we will get our answer as
110

Hope this answerd ur question.

Answer 5

@Mickel
Nice explanation

Answer 6

I don't know...😞😞

Answer 7

Thanks you all

Answer 8

//these two lines are declaring a and b as integar type and assaigning them value
int a=0;
int b=1;

/* this is for loop in which firstly i is initialized as 0 and than condition i<= b will be checked if condition is true than control will flow inside { } and will execute whatever code is written inside {} and final part of for loop will increase value of i by value of 1 after each execution. */
for (int i=0;i<=b+1;i++){

/* if condition it will give true or false if condition is true whatever inside {} is present will be executed. */
if (i==2){

// println method will print a //
System.out.println(a);}

/* IF if condition returns false than control flows to else and executes whatever code is written inside {} */
else{
System.out.println(a+b);}

}
/* AS FOR LOOPS CONDITION IS i<=b+1 it means for loop will be executed 3 times
FIRST TIME WHEN i=0 OUTPUT WILL PRINT else PART THAT MEANS a+b WHICH WILL BE (0+1) = 1
WHEN SECOND TIME LOOP WILL RUN i=1 AGAIN else CONDITION WILL PE PRINTED HENCE AGAIN 1 WILL PE OUTPUT
NOW WHEN LOOP WILL RUN FOR THIRD TIME i=2 AND THAT MEANS if CONDITION WILL BE TRUE AND HENCE THIS TIME OUTPUT WILL BE a WHICH IS 0.
AND HENCE TOTAL OUTPUT WILL BE 110. */

Output is 110