JAVA Array of random numbers in range

Question

Hi, guys!
I need help from local experts:
I made a code that generates random numbers in the array, but I needt it to pick random numbers in some particular range(now it's picking any).
I'm trying to figure out how to do it myself, but I have a biger problem that I have a really hard time to resolve:

I need it to use a foreach loop to print all elements of the array accurate to four decimal places, and pass the array of doubles to a method that executes as follows:
uses a for loop and a Math class method to round up each element to its nearest integer.
creates a 10-element array of ints named temp.
uses another for loop to cast each element of the double array to temp.
returns temp

That's what I really need help with.
Please, help me to correct it. Any help is much appreciated!
Here is my code:
https://code.sololearn.com/czRXyUwyqaYT

Answer 1

import java.util.Random;

public class RandArray {

private static Double[] anArray = new Double[10];
private static Random rand = new Random();

public static void list()
{

for(int i=0;i<anArray.length;++i) anArray[i]=
rand.nextInt(10)+rand.nextDouble();
}

public static void print() {
for(double n: anArray)
System.out.printf("%.4f \n", n);
}

public static int[] copy() {
int[] temp = new int[10];
for(int i=0;i<anArray.length;++i) temp[i]=
(int)Math.round(anArray[i]);
return temp;
}

public static void main(String args[])
{
list();
print();

int[] arr = copy();
for (int i : arr)
System.out.println(i);
}
}

Answer 2

Thank you so much for the response! How to print sorted numbers in 1 line? I cant manage to accomplish it