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Need help with pointers
#include <stdio.h> int main() { char *s= "hello"; char *p = s; printf("%c\t%c", p[0], s[1]); } when executed output was : h e why??? in printf.. i typed p[0] not s[0]... still it prints h need some explanation here..
1 Respuesta
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p is of the same type as s. after the assignments p and s are both of the same value (ie the address of the first character of the string "hello")
So p[0] is the same as s[0], which is h.