Why is there no output for the following code?

Question

#include <iostream>
#include <string>
#include <sstream>
using namespace std;
string isAutomorphic(){
string a;
int num;
int is;
int c;
string f;
string r;
string x;
stringstream stream;
cin >> a;
stream << a;
stream >> num;
int b = num * num;
stream.str("");
stream << b;
stream >> x;
int z = num;
is = x.find_last_of(z);
stream.str("");
stream << num;
stream >> r;
if(is == (r.size() - (r.size() - is))){
f = "Yes, it is an automorphic number.";
}
else{
f = "No, it is not an automorphic number.";
}
stream.str("");
return f;
}
int main() {
isAutomorphic();
return 0;
}

Answer 1

Try putting this code:

cout << isAutomorphic() << endl;

instead of just isAutomorphic()

inside the main() function.

Answer 2

Thanks!

Answer 3

Oh, I edited the code, it works, but it's stuck on "Yes, it is an automorphic number."

Code:
#include <iostream>
#include <string>
#include <sstream>
using namespace std;
string isAutomorphic(){
string a;
int num;
int is;
int c;
string f;
string r;
string x;
stringstream stream;
cin >> a;
cout << "Your number: " << a << endl;
stream << a;
stream >> num;
int b = num * num;
cout << "Squared: " << b << endl;
stream.str("");
stream << b;
stream >> x;
int z = num;
is = x.find_last_of(z);
stream.str("");
stream << num;
stream >> r;
if (is != (r.size() - (r.size() - is))){
f = "No, it is not an automorphic number.";
}
else if (is == (r.size() - (r.size() - is))){
f = "Yes, it is an automorphic number.";
}
stream.str("");
return f;
}
int main() {
cout << isAutomorphic() << endl;
return 0;
}