Python result none

Question

I am trying to do a dice roller.
I have done a generic die
I wrote a multiple dice roll script but i get a none as a final roll

How can i avoid this none

import random

def de(cote):

b=cote
return (random.randint(1,b))

def des(nombre,cote):

a=nombre #nombre de des a rouler
b=cote #valeur des des a rouler
c=1 #compteur

while c<=a:
c=c+1
print(de(b))

print(des(3,6))

Answer 1

like you said, if I run it with out print by calling de() none dosen't show. Thanks for your time and help!!

Answer 2

you defined variable b twice
you defined b inside de(cote) and you called it de(b) while b is defined within de() and it has value cote, which has a value b which is cote .......

Answer 3

I see the mistake and I think I found a way to improuve my code. Thank you for the help.

Answer 4

I made this modification but still have the none after my five roll
import random

def de(nombre,cote):
a=nombre
b=cote
c=1

if a<=1:
return (random.randint(1,b))
else:
while c<=a:
c=c+1
print(random.randint(1,b))

print(de(5,6))

Answer 5

you dont necessarily have to make variables a and b, because you can just call nombre and cote, and the rest of your code looks good and you've made a really good improvement

Answer 6

import random

def de(nombre,cote):
c=1

if nombre<=1:
return (random.randint(1,cote))
else:
while c<=nombre:
c=c+1
print(random.randint(1,cote))

print(de(5,6))

outputs 5 numbers then none because nombre is greater than 1 (its 5) and c starts with 1 and is after every random added by 1 so after 5 random numbers its 6 and will output none because there is no other if or elif or else statement that is true

Answer 7

I can't figure out how to avoid the output of none

Answer 8

i tried some things and found out that the problem is in the
pribt(de(5,6)) part