How to find maximum and minimum value in number array?

Answer 1

Set the first element to max(min), and then search trough all the elements, asking if the next one is higher(lower) than max(min) value. It's very easy, try it

Answer 2

@dariusPianotised
Consider this piece of code memory efficient

for(int i=0;i<ARRAYSIZE(a);i++)
{
cout<< "\nEnter value: ";
cin>> a[i]; // puts values in array
if(i==0)
{
minValue=a[0];
maxValue=a[0];
}
else if(minValue>a[i]) minValue=a[i];
else if(maxValue<a[i]) maxValue = a[i];

}

Answer 3

#include <iostream>
#include<Windows.h> //Include Windows to use ARRAYSIZE
using namespace std;
int main () {
int minValue,maxValue;
const int size = 10; // modifying this value will allow for less/more numbers to be entered by the user
int a[size];
cout<<"Enter your values:";
for(int i=0;i<ARRAYSIZE(a);i++) {
cout<< "\nEnter value: ";
cin>> a[i]; // puts values in array
}
minValue=a[0];
maxValue=a[0];
for(int i=1;i<ARRAYSIZE(a);i++) {
if(minValue>a[i]) {
minValue=a[i];
}
else if(maxValue<a[i]){
maxValue = a[i];
}
}
cout<<"Maximum number is: "<< maxValue << endl;
cout<<"Minimum number is: "<< minValue << endl;

return 0;
}