What is the output of this code. Explain(dumb it down)

Question

What is the output of this code?
int a = 8;
int b = ++a;
if(a > 5)
b -= 3;
else
b = 9;
Console.WriteLine(b);

Answer 1

int a = 8; /* sets a to 8 */
int b = ++a; /* increases a by one, so a is now 9, and also sets b to this value, so b is now also 9 */
if(a > 5) /* a is 9 and 9 > 5 is true, so we enter the if (next line) */
b -= 3; /* b -= 3 is the same as b = b - 3. b was 9 before, so now b is 9 - 3 = 6 */
else /* the if was true so we can skip the else part */
b = 9; /* skip */
/* now b is still 6, so the output will be 6 */

Answer 2

ans is 2

Answer 3

6. because u have an if there where it says if a>5 and it is! because a = 8. and the compiler is doing b = 9 - 3 //(9 because a is now = to a + 1). if a was < 5 , the compiler jumped to the 'else'

Answer 4

1. a is 8
2. a is 9, b is 9
3. is 9 > 5? Yes
4. so b is 6
5. skip else
6. skip
7. print 6

Answer 5

answer is 6

Answer 6

what is the value of b ?
b = 1 if 2+2 == 5 else 2
2

Answer 7

https://jsfiddle.net/ppjyksw4/

We start with two defaults.

A is 8. B is equal to a plus 1.

Steps
1. A is declared.
2. B is set to A plus 1.
3. logic: if a is bigger than 5, b is equal to 8+1-3. If A is equal to or smaller than 5, b is 9.

Since A is 8, obviously larger than 5, B is 8+1-3

Answer 8

the answer is 6

Answer 9

6

Answer 10

the answer is 6

Answer 11

What is the value of b?
b = 1 if 2+2 == 5 else 2