Why is the output of the code :5 ?It should be zero right?

Question

https://code.sololearn.com/cr5UFRBePumq/?ref=app

Answer 1

Becouse yours second loop don’t work when you use yield in your function.yield it is a generator and generators you can use one time.

Answer 2

The code that is needed to run this task properly is:

def count_to_5():
for i in range(1,6):
yield (i)

c=count_to_5()
for i in c:
print(i)

So "c" is a generator object. It stays connected with the function. You can only iterate once over it, then it is exhausted.
If you don't wanted the generator to iterate in a loop, you can get result by calling:

next(c)

Each time this is called, a new number of the result will be given. If you call more than the generator can give back, you will run in a StopIteration Exception. A generator has no length, as it does not have any data stored.

Answer 3

Thanks

Answer 4

read about generator and itaerator necessarily

Answer 5

What does next(c) do?

Answer 6

Because of generator ..... only first for loop consider.....so n+=1 but not n -=1

Answer 7

Yes

Answer 8

next(c) does exctly do one step in iteration. You can trigger this in your code, but mostly iteration is done in a for loop.