Can you explain this code???

Question

var a= [];
for(var i=2;i>0;i--){
a[i]=i;
}
console.log(a.length*i)

How the answer is 0.
As a.length=3 and last value of i is 1
Why answer isn't 3???

Answer 1

~ swim ~
Thank you. I generally don't understand for loops fully.
Your answer makes all clear.

Answer 2

🇧🇩🇳‌🇴‌🇷‌'🇼‌🇪‌🇸‌🇹‌🇪‌🇷‌ does it mean. inside loops last value of i is 1 and outside of it i becomes 0.

Answer 3

~ swim ~ if last value of i is 0
Why a[0] is undefined ???

Answer 4

The loop stops AFTER i becomes 0.
So, 0.

https://code.sololearn.com/W41h6b3WbOuA/?ref=app

Answer 5

The last value of i is not 1 it is 0.
See this to understand why it is 0.
https://www.sololearn.com/learn/JavaScript/1140/

Answer 6

By tracing the code
1- a[2]=2. a[]= {null,null,2}; and the value of i will be decreased by one so i=1
2- a[1]= 1. a[] = { null,1,2} ; and the value of i will be decreased by one so i = 0 and this value won't meet the condition of the loop as the loop ask for i any value greater than 0 once it be 0 it won't meet the condition so the loop will be broken up and the last value of i is equal to 0 so by multiplying i by the a.length it will result in zero