Why I get output:0?

Question

import java.util.Scanner;
public class Program{
public static void main(String [] args){
Scanner input=new Scanner(System.in);
int x=input.nextInt();
int y=2;
int p=(y/x)*100;
System.out.println(p);
}
}

Answer 1

In Java, integer/integer always results in integer. fractional part is discarded.

example :
```
System.out.println(5/2); //2
```
Here 5 and 2 are both integer literals. So result will also be integer (neither float nor double).

5/2 should be 2.5 but 0.5 (fractional part) is discarded as it's an integer value.

Hope you can understand why your example shows 0. If you can't figure out , feel free to ask.

Answer 2

Ebney Samrat
import java.util.Scanner;
No brackets after Scanner

Answer 3

Ah ok.