Program is still taking input after System.exit().

Question

Still it is taking two numbers as an input after using System.exit(0).

public class Calci {
private static double add(double num1,double num2) {
return num1+num2;
}

private static double sub(double num1,double num2) {
return num1-num2;
}

private static double multiply(double num1,double num2) {
return num1*num2;
}

private static double divide(double num1,double num2) {
return num1/num2;
}
public static Scanner sc = new Scanner(System.in);
public static void main(String[] args) {
while(true) {
System.out.println("This is a simple calculator.\n\nFunctions :-"
+ "\n1. Addition."
+ "\n2. Subtraction."
+ "\n3. Multiplication."
+ "\n4. Division."
+ "\n5. Exit."
+ "\nI want to do ");
int ch = sc.nextInt();
System.out.println("Enter two numbers.");
double num1 = sc.nextDouble();
double num2 = sc.nextDouble();
switch(ch) {
case 1:
System.out.println(add(num1, num2));
break;
case 2:
System.out.println(sub(num1, num2));
break;
case 3:
System.out.println(multiply(num1, num2));
break;
case 4:
System.out.println(divide(num1, num2));
break;
case 5:
System.exit(0);
break;
default:
System.out.println("Invalid Input. Pls try again.");
}
}

}

}

Answer 1

double num1=0, num2=0;
if (ch != 5) {
System.out.println("Enter two numbers.");
num1 = sc.nextDouble();
num2 = sc.nextDouble();
}