Explain the question

Question

def f(x):
return(2*x+1)
def g(x):
return(x-1)
print(g(f(2)-f(g(2)))

Answer 1

This is a nested function which performs a specific equation with given parameters.

Equation of "g" :
---> x - 1
Equation of "f" :
---> (2 * x) + 1

Then we will just solve those each of those functions until we got only 2 numbers and evaluate.

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First, let's focus on the main equation which is:

g (f(2)) - f (g(2))

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# First solve the first term: g(f(2))
f(2) = 2 * 2 + 1
f(2) = 5
---> g(f(2)) --->g(5)
👇
g(5) = 5 - 1
g(5) = 4

So now the first term is 4

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# Next is the second term: f(g(2))
g(2) = 2 - 1
g(2) = 1
---> f(g(2)) ---> f(1)
👇
f(1) = 2 * 1 + 1
f(1) = 3

So now the second term is 3

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Therefore:
g(f(2)) ---> 4
f(g(2)) ---> 3

4 - 3

>> 1

If this is still not clear, then please feel free to ask. Thanks!

Answer 2

《 Nicko12 》 thank you so much