What is the output of this code and why ....

Question

int main()
{
printf("%u",-1);
return 0;
}

Answer 1

%u stands for unsigned, so if you try to output -1 as unsigned, you will go out of scope value, and print unsigned_max_value
If you would try printing -2, you would get
unsigned_max_value -1 etc.

At least I think it works like that

Answer 2

U mean to say that am i printing the unsigned maximum values of int ?

Answer 3

Yes, you are printing max unsigned int value, which is 2^32-1