Why is my code showing an output of 4, 4, 8 despite writing a code for 1??

Question

In this code:

#include <stdio.h>

int main() {
printf("int: %ld \n", sizeof(int));
printf("float: %ld \n", sizeof(float));
printf("double: %ld \n", sizeof(double));
printf("char: %ld \n", sizeof(char));

return 0;
}

Answer 1

I didn't understand your question. explain "despite writing a code for 1"? you wrote the code to print the memory size of each variable.

Answer 2

Actually size depends on your operating system architectures. Your question is not clear u asking writing code for 1 char size is 1 so it should be print 1 which u have already done

Answer 3

What code should I write to print the output of 1??