Why can't I pass value via url in php?

Question

https://code.sololearn.com/w601NMDkgDQ6/?ref=app

the id1 isn't working when I use the get method but the id is working

Answer 1

Aah finally get it
You have a space there at line 11, and that space is translated as %20 in the code

'&id1 ='.$show['cart_id']

You see the space between &id1 and the = sign ...

Answer 2

Explain "did not work", please?
Show a sample of the link ...

Answer 3

Yes, but only for debugging stage, only so you can see clearly, whether the URL built from resultset is valid ...

Answer 4

How the URL look like? I need to see how your code is doing when it builds the URL.

Undefined index means there's no such element in the $_GET array, identified by "id1" key.

Answer 5

Ipang oh yes!!!! thank you so much, fixed it already.

Answer 6

Azalea Pls avoid going on private to solve questions. Keeping public makes solutions available to everyone.

Answer 7

Try to dump the URL as text on screen, look for something that doesn't fit in.

There seems to be a missing <tr> but that probably was not copied over.

Answer 8

Ipang what do you mean?

Answer 9

I mean, instead of making a hyperlink in the table cell, print the URL on the screen to see if something is not right.

Answer 10

Ipang the href? i will echo it?

Answer 11

I tried running it, only the value of id was retrieved when I use the get method, but the id1 value did not work Ipang

Answer 12

Ipang I have this on my editOrd.php

$a =$_GET['id'];
$b=$_GET['id1'];

echo $a;
echo $b;

but the b has an error it says undefined index

Answer 13

I wanted to see an exsample of the URL that are printed on screen. Do they form a valid URL? what value does the 'id1' have in the URL;

DM isn't working for me, I can only read, not reply ...

Answer 14

Ipang
http://localhost/fold/editOrd.php?id=5&id1%20=2