Can anyone tell me working of this code.

Question

This is code
#include <iostream>
using namespace std;

int main() {

int x=5;
x=x*8%x;

cout<<x;
return 0;
}

it's output is 0.
even when I changed 8 with any other number it is give output also 0.

Answer 1

Hmm...
x = 5
x = 5*8 = 40 % 5 = 0
print x = 0

x = 8
x = 8*8 = 64 % 8 = 0

So far there is no error in the code and it gives the right output

Answer 2

@Rajesh Kumar(Rj) It would still output 0 (Refer to mine or M Rey's code)

Answer 3

a*x%x will give 0 for all integers a, as a*x always is divisible by x.

Answer 4

yeah, because 5*8=40

and 40%5=0;

u can use for 8 any other number and it will be always returns 0.

Answer 5

if I change 8 with 5 .

Answer 6

test it, but i think it will returns 0

Answer 7

u should change ur x