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How do I write a try-throw catch exception to find the square root of the number input from scanner and use exception for -ve no

try-throw catch block if the number enter from the scanner is -ve number and check it using try-throw catch exception

18th Jul 2017, 2:05 PM
Alao Abiodun
Alao Abiodun - avatar
1 Respuesta
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try-throw? What like: try{ throw new Exception(); } ? Do you happen to mean a Try catch? Throw is not the same. It would be helpful to tag the language you are referring to, 'Java'. So, first you need to check if the input is a number. Since you want to use a try catch, I assume the method you want to use is some type of convertion. Example/ (Assume scanner is named sc) try{ int input = Integer.parseInt(sc.next()); } catch(InputMisMatchException e){ // was not a number } Then, you can take the sqrt of the number. If you don't want to define your own sqrt method, you can use the one in the math class. Example extended/ try{ double rootInput = Math.sqrt(Integer.parseInt(sc.next())); // sqrt of input // deal with this however you want to if(Double.isNaN(rootInput)) { // Negative root } } catch(InputMisMatchException e) { // Failed to Cast (Not an int) }
18th Jul 2017, 3:43 PM
Rrestoring faith
Rrestoring faith - avatar