In int x = sample [1] [0]; of array, why [1] has not been executed?

Question

It`s only executing [0] which has a value 4. But why not the first array?

Answer 1

Its only printing "4" because you're just printing that element at the specifed index. If you want to print all the data i recommend you use a nested for loop. Also be careful of going arrayIndexOutOFBounds because some "array of arrays" have different lengths.

Answer 2

int x = myArr [1] [0];
Arrays starts with position 0.
[1] refers to the 2nd position of your myArr. In this case, {4}.
[0] refers to the 1st position of myArr [1] (i.e.: {4}) which is 4. hence, 4 is being executed

if u want x to be an integer from the first array (i.e.: 1, 2 or 3) then you can change the value of int x to the following:
int x = myArr[0][0] for x = 1
int x = myArr[0][1] for x = 2
int x = myArr[0][2] for x = 3

Answer 3

can you put program snippet in details?

Answer 4

public class Program {
public static void main(String[] args) {
int[ ][ ] myArr = { {1, 2, 3}, {4}, {5, 6, 7} };
myArr[0][2] = 42;
int x = myArr[1][0];

System.out.println(x);
}
}