im a new learner and i have a simple question.

Question

hi everyone i just have a simple question about my code...
i gonna ask on this part in my own output wich is :(1,2,3,4,5,6,7,8,9,10,).
what to do to remove the last ","?
im a new learner so my code is simple sorry. xD
and if u guys can give me advices to improve the code or givin me general tips then... please DO!.thanks.
btw that's my simple code:
https://code.sololearn.com/cM5OcwHs0U70/#cpp

Answer 1

int a[]={1,2,3,4,5,6,7,8,9,10};
int size = sizeof(a) / sizeof(a[0]);
cout<<"the elements are:-\n";

for (int x=0; x<size; x++)
{
cout <<a[x]<< (x < size-1? "," : "\n");
}

Answer 2

Ặňặ Ǯǿmry MặƧđař Ặnśậk

I guess you have trouble understanding the array size calculation (pointer arithmetic) and ternary conditional operator, right?

Answer 3

This line

int *p = new int;

allocates 4 bytes of the heap space to the program (a.k.a dynamic allocation). From this point, the pointer p is able to access to that 4 bytes of the memory and do calculation and other stuff and finally must be reclaimed by delete(p). But that's not the point of my earlier question.

int size = sizeof(a) / sizeof(a[0]);

Here, a holds the base address of the whole array. It acts as a pointer to the first element of the array. So, by making a query of the size of a, you get the whole size of the array as byte. Since the array has integer type, the sizeof gives you

total number of items * size of integer type = 10 * 4 = 40

Then, to get the actual number of items you can simply divide the result by the size of a single integer or the first element of the array as

40 / sizeof(int)
or
40 / sizeof(a[0])

Answer 4

Ặňặ Ǯǿmry MặƧđař Ặnśậk

" can u help me to understand your code? or give me a vid or the name of this lesaon? it works but i didnt learn yet how to do that. "

You didn't mention anything about your problem. you just vaguely jumped into some topics related to dynamic memory allocation.

Anyway. I'm short in time right now, so I refer you to cplusplus portal. The post explains it in more details.

http://www.cplusplus.com/forum/articles/14631/

Answer 5

add a simple if statement before cout a[x]
for (int x=0; x<10; x++){

if(x<9){
cout <<a[x]<<"," ;
}
else{cout <<a[x];}
}

Answer 6

C++ Soldier (Babak) thnx i gonna try that soo as possible ^^

Answer 7

Tomer Sim thank you i though in that but i wasn't sure 😅

Answer 8

C++ Soldier (Babak) can u help me to understand your code? or give me a vid or the name of this lesaon? it works but i didnt learn yet how to do that..

Answer 9

C++ Soldier (Babak)
to be honest im not sure 100% i mean i dont have ideas to practice😅 but i understand the pointer and stack and the heap i gonna tell you how i understood it and current me if im wrong, for example:
int *p= new int
*p=5
the p itself its the code (idk what's the word exactly in english srry, tell me the right names if u can)
that code its like exist in the stack and the "*" itself points to the value of it which is located in the heap which is 5. i hope im right XD

Answer 10

C++ Soldier (Babak) noo bro i understand this i just was asking about this part (x<size-1?",":"\n");
cause i didnt learn it yet, and btw thanks for explaining the heap i got some new informations ^^.

Answer 11

C++ Soldier (Babak) srry dude my bad i be dumb sometimes 😅 , and thanks a lot