How to generate a function that shows this kind of character art?

Question

Function(5)
Out:
* *
* *
*
* *
* *

Answer 1

You have to find a logic behind the pattern... The simplest logic is:

- set n to be row count (5 in example)

- for any 'c' in n print current row pattern

- Any row its composed by 'n' characters and 1 or 2 of they must be asterisks which depends on 'c'.
If you see at c=0 (first line) the first and last chars are *. At second line (then c=1) the second and last less one chars are *. You can see a logic? At 'c' row you have to set the 'c' and 'n-c-1' char (checking if they have same value like at c=2 in your example)

Answer 2

This is more fun, type your name

https://code.sololearn.com/cid3GT7KjUBS/?ref=app

Answer 3

n=int(input())
[print('{:^40}'.format('*' if i==0 else '*'+' '*(abs(i*2)-1)+'*')) for i in range(int(-n/2),int(n/2)+1) ]

Answer 4

Maybe his/her is an assignement 😒

Answer 5

this is the easiest way to do so.
print("* *")
print(" * * ")
print(" * " )
print(" * * ")
print("* *")

Answer 6

Actually i want that by using nested loops

Answer 7

okk