What will be the output of following program? Assume integer is of 2 bytes......

Question

#include<stdio.h>
int main()
{
int a=32770;
printf(“%d”,a);
return 0;
}

Answer 1

Aman Kumar it again starts from lower value....

for example, short int has limit -32768 to 32767.... so, it will work properly within this limit...

with 32768 as value, it will start with lower bound i.e. -32768
with 32769 as value , it will add one to lower bound i.e. output will be -32768 + 1 = -32767

try with other values if you wish with below code snippet in playground :

short int a = 32780;
printf("%i",a);

Answer 2

Ketan Lalcheta thanks. I get it.....