By C function How to check if string mirrored or not?

Question

I tried this but didn't work:

#include <stdio.h>
#include <stdlib.h>

void check_string_mirrored(char *str, int size )
{
int i;
for(i=0; i<size; i++)
{
if(str[i] == str[size-i])
{
printf("string is mirrored\n");
}
else
printf("string is not mirrored\n");
}
}
int main()
{
char s[5]= "ARBRA";
check_string_mirrored(s,5);
return 0;
}

Answer 1

You need to compare str[i] with str[size-i-1].

#include <stdio.h>
#include <stdlib.h>

void check_string_mirrored(char *str, int size )
{
int i;
int mirrored = 1;
for(i=0; i<size; i++)
{
if(str[i] != str[size-i-1]) {
mirrored = 0;
break;
}
}

printf("string is");
printf(mirrored ? "" : " not");
printf(" mirrored\n");

}
int main()
{
char s[5]= "ARBRA";
check_string_mirrored(s,5);
return 0;
}