Lambda question

Question

why does this code prints 666?
The function returns a lambda function or actually it returns 3 functions (due to the range?). When I then pass 3 as an argument - what happens?
As simple as this looks I don’t get it yet.

def ll():
return [lambda x:i*x for i in range(3)]

for l in ll():
print(l(3), end="")

Answer 1

https://docs.python.org/3/faq/programming.html#why-do-lambdas-defined-in-a-loop-with-different-values-all-return-the-same-result

Answer 2

Thanks a lot! RTFM advice to me ... but the manuals are so long :)