Why the sum(result) stop summing when I add a variable(b) to do an average. -_-

Question

#include <iostream>

using namespace std;

int main()
{
cout << "AVERADGE OF NUMBERS: " << endl;
double result(0);
int b(1);
int a(0);

for(int x=1; x<100; x++)
{
cin >> a;
result=(result+a)/b;
cout << result << endl << endl;
b++;
}
}

Answer 1

It is still summing but you are using result everytime in the for loop. Example: if result = 100, a = 100 and B = 3 the new result will become 100+100=200 200/3 is something like 66,..... The second time this value will be used in the calculation ex: 67 + 100 = 167 167/4 (new B value) = 43,...

Answer 2

waw thx m8... am i fully retarded? as they say answers bring more questions ;;_;;

Answer 3

#include <iostream>

using namespace std;

int main()
{
cout << "averadge: "<< endl << endl;

double total=0, averadge=0, entry=0;

for (int x=1; x>0; x++)
{
cout << "entry" << x <<": ";
cin >> entry;

total+=entry;
cout << "total: " << total << endl;

averadge=total/x;
cout << "averadge: " << averadge << endl << endl;
}
}