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Problem with asteric(*) variable and type
When I write this code it shows error. a,*b='abcdef' print(*b,type(*b)) It throws a error that type() takes 1 or 3 argument. How to know the type of '*b' and can anyone give me a example of type() taking 3 arguments. What it actually mean?
9 Réponses
+ 4
You can do it like this:
a,*b='abcdef'
print(*b,type(b))
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Thanks a lot. The article clears the confusions.
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https://docs.python.org/3/library/functions.html#type
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thank you ^_^
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Thanks ^_^
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now it shows <class 'list'>
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I wanted to know the type of (*b)