could someone explain this?

Question

// why a = 0x28ff10 ?
// what is *(a + 2) doing ?

#include <iostream>
using namespace std;

int main() {
int a[4] = {1,2,3,4};

cout
<< a << endl
<< *(a + 2) << endl
<< 0x28ff10;
}

Answer 1

cout<<a; is giving you location of a[0] and cout <<*(a+2); is giving you value at a[2]

Answer 2

0x28ff10 is a hexadecimal number literal (can be recognized by the leading "0x" that just states that the following literal is hexadecimal, i.e. to the base of 16).

Answer 3

Thanks to both

Answer 4

How is (a + 2) possible? It sounds like it's trying to add the literal 2 to an array of integers which should spit out a compilation error.