Please help me with this code.

Question

# Write a Python program to read an integer and find its reverse. Note: if user enter 1234 than the output should be 4321.

while True:
print("Enter a number to get the reverse of it: ")
n = []
a = int(input())
n.append(a)
b = n.reverse()
print(b)

Answer 1

Shrish Kumar Saini , there is also an other way to do this task, without using string conversion:

reversed_number = 0
n = 128
while n > 0:
dig = n % 10
n //= 10
reversed_number = reversed_number * 10 + dig
print(reversed_number)

Answer 2

your list will contain the inputed number. reversing a list of one item wil not do something.

n = [1234]

after reversing it it will stay
n = [1234]

try to convert the number to string and then reverse that string and convert reverted string back to integer.

n = str(a)
n.reverse()
n = int(n)
print(n)

or just do this:

a = input()
a.reverse()
a = int(a)
print(a)

Answer 3

The easiest route is to convert to string, flip it then convert back to integer🤷

Check this code

https://code.sololearn.com/cTgx4gYfpto8/?ref=app

Answer 4

thank you everyone :)

Answer 5

You can simply do:

word = str(input())
word = word[::-1]
print(word)