Can anyone please explain the working of below code snippet how pointer is pointing and printing the values.

Question

#include<stdio.h>
struct list {
int a;
char *ch; }
s[] = {18, "GATE", 19, "CSE", 20, "COURSE"};
int main() {
struct list *ptr = s;
printf("%s\n", ptr++->ch);
printf("%s\n", (++ptr)->ch);
printf("%d\n", (--ptr)[1].a);
printf("%d\n", ptr[0].a);
return 0; }

Answer 1

I tried my best explaining with comments in the code bit. But first you must know the following shorthands:

ptr->ch; is the same as: *(ptr).ch

(ptr++)->ch; is the same as: *(ptr).ch; ptr++;

ptr[1]; is the same as: *(ptr+1).a;

https://code.sololearn.com/cfG45zKw4GRP/?ref=app