Seperate Even and odd elements of an array using pointers in C program

Question

Please help me out with this, i am newbie here ,i have to complete it today

Answer 1

Instead of making an array to put the integers, you should create a pointer to an integer array. Then just do the same thing, check each number and output if even or odd when needed

Answer 2

Provide your attempt. I'll need that today.

Answer 3

How to do it using pointers

Answer 4

This question has a familar ring. See the challenge below:
https://www.sololearn.com/post/1269153/?ref=app

Answer 5

#include <stdio.h>

int main()
{
int a[10],i,n,*p;
printf ("enter the number of elements:\n");
scanf("%d",&n);
printf ("enter elements: \n");
for(i=0;i<n;i++)
{
scanf("%d",&a[i]);
}
printf("------------------------\n");
printf ("even numbers are: \n");
for(i=0;i<n;i++)
{
if(a[i]%2==0)
{
printf ("%d\n",a[i]);

}
}
printf("-------------------------\n");
printf ("odd numbers are: \n");
for(i=0;i<n;i++)
{
if(a[i]%2!=0)
{
printf ("%d\n",a[i]);
}
}
return 0;
}