Can someone help me with this code.

Question

Like I want a user to input 10 integers(marks) in the same line and then set a pass mark of her choice.
The output should be the count of the marks that are above or equal to the pass mark
https://code.sololearn.com/cYA77yGghkNr/?ref=app

Answer 1

array<int,10> saved = {}; // array is not predeined keyword , you may trying vector thrn use vector innplace of array
array<int,10> users;
cin >> users; //thid only accept single input
cin >> pass;

for (int i=0; i<users.size(); i++){
saved.push_back(users);
for (int x: saved){
if(int x: saved>= pass){ // wrong syntax for comparision...
count = count + 1;
}
}
}
cout << count << endl;

Corrected way are :

vector<int,10> saved = {}; //declare vector

int marks;

for (int i=0; i<10; i++){
cin>>marks; // take a input of int
saved.push_back(marks); // add to vector
}
for (int x: saved){ // read vector
if( x >= pass){ // compare x with pass marks
count = count + 1;
}
}

Hoping you can reform owl code again.. Hope it helps...

edit: add vector header
#include <vector>

your 2nd of header is invalid. remove it..

Answer 2

Set pass value and
vector<int> saved(10); declare vector of size 10 with all set to 0.

Instead use vector<int> saved{};

int pass = 5; // set pass marks or take input

Answer 3

Jayakrishna🇮🇳 thanks it's working perfectly now.

Answer 4

Tsering Jayakrishna🇮🇳 🙏

Answer 5

Jayakrishna🇮🇳 it prints out 20 for ever inputs😔

Answer 6

You can check it I edited it

Answer 7

You're welcome...

edit: Siyabonga Brian
don't take input for pass in loop.. it ask input in each iteration. take before loop.